CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In a resonance tube, the first resonance with a tuning fork occurs 16 cm and second at 49 cm. If the velocity of second is 330 m/s, frequency of tuning fork is:

A
500Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
300Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
330Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
165Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 500Hz
For closed pipe
l1=v4n and l2=3v4n
v=2n(l2l1)

n=v2(l2l1)

n=3302(0.490.16)
n=500Hz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Forced Oscillation and Resonance
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon