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Question

In a resonance tube, the first resonance with a tuning fork occurs 16 cm and second at 49 cm. If the velocity of second is 330 m/s, frequency of tuning fork is:

A
500Hz
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B
300Hz
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C
330Hz
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D
165Hz
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Solution

The correct option is A 500Hz
For closed pipe
l1=v4n and l2=3v4n
v=2n(l2l1)

n=v2(l2l1)

n=3302(0.490.16)
n=500Hz

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