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Standard XII

Physics

Resonance in Sound Waves

A tuning fork...

Question

A tuning fork of frequency $500 Hz$ is sounded on a resonance tube. The first and second resonances are obtained at $17 cm$ and $52 cm .$ The velocity of sound is

170 m/s

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350 m/s

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520 m/s

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850 m/s

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Solution

The correct option is B $350 m/s$
$\frac{3 λ}{4} - \frac{λ}{4} = \frac{λ}{2} = 52 - 17 = 35 cm = .35 m$
$λ = 0.70 m$
$v = ν λ = 500 \times 0.7 = 350 {ms}^{- 1}$
Option B is correct.

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Similar questions

In a resonance tube experiment when a tuning fork of frequency 500 Hz is sounded over it, the first and second resonances are obtained at 17 cm and 52cm. the velocity of sound is

Ans is 350 m/s.

Please give detailed explanation as I won't be able to understand concise answers.

Q. In a resonance tube the first resonance with a tuning fork occurs at

16

cm and second at

49

cm. If the velocity of sound is

330

m/s, the frequency of tuning fork is :

Q. In a resonance tube, the first resonance with a tuning fork occurs

16 c m

and second at

49 c m

. If the velocity of second is

330 m / s

, frequency of tuning fork is:

Q. In an experiment for determination of velocity of sound by resonance tube methods using a tuning fork of frequency

512 H z

, first resonance was observed at

30.7 c m

and record was obtained by

63.2 c m

. The maximum possible error in velocity of sound (actual velocity of sound in air is

332 m / s

) is:

Q. A tuning fork is used to produce resonance in a glass tube. The length of the air column in this tube can be adjusted by a variable piston. At room temperture of

27^{o} C

, two successive resonances are produced at

20 c m

and

73 c m

of column length. If the frequency of the tuning fork is

320 H z

, the velocity of sound in air at

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A tuning fork of frequency 500 Hz is sounded on a resonance tube. The first and second resonances are obtained at 17 cm and 52 cm. The velocity of sound is

The correct option is B 350 m/s3λ4−λ4=λ2=52−17=35 cm=.35 mλ=0.70 mv=νλ=500×0.7=350 ms−1Option B is correct.

A tuning fork of frequency $500 Hz$ is sounded on a resonance tube. The first and second resonances are obtained at $17 cm$ and $52 cm .$ The velocity of sound is

The correct option is B $350 m/s$
$\frac{3 λ}{4} - \frac{λ}{4} = \frac{λ}{2} = 52 - 17 = 35 cm = .35 m$
$λ = 0.70 m$
$v = ν λ = 500 \times 0.7 = 350 {ms}^{- 1}$
Option B is correct.