Question

In a right triangle, with respect to an acute angle $\theta$, the opposite side is twice the adjacent side. The value of cosec $\theta$ is

• A. √5/2
• B. √3/2
• C. √2/3
• D. 5/2

Answer 1

The correct option is A

√5/2

Given that Opposite side/Adjacent side = $\frac{2}{1}$ = $\frac{2x}{x}$

Take opposite side = 2x

Adjacent side = x

Using Pythagoras theorem,

$A{C}^2=A{B}^2+B{C}^2$

AC = = $\sqrt{5}$ x

Cosec $\theta$ = Hypotenuse / Opposite side =$\frac{\sqrt{5}}{2}$