Question

In a school, $437$ boys and $432$ girls have been divided into classes so that each class has the same number of students and no class has boys and girls mixed. What is the least number of classes needed?

Answer 1

Each class should have the maximum number of students.

So, HCF of $437,342=19$

HCF is also the factor of difference of the number.
$\therefore$ Number of classes $=\frac{437}{19}+\frac{342}{19}=23+18=41$ classes