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Question

In a series RLC circuit R=300Ω,L=60 mH, C=0.5μF,V=50 V, ω=104 rad s1.Find the voltage across capacitor:

A
30 V
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B
20 V
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C
60 V
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D
50 V
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Solution

The correct option is C 20 V
Current in the circuit is given by:

I=V|Z|

I=VR2+(ωL1ωC)2

I=503002+(60×103×10410.5×104×106)2

I=503002+4002=110A

Voltage across capacitor is:

Vc=IXc=IωC=110×200=20V

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