Question

In a silicon diode, the reverse current increases from $10\mu A$ to $20\mu A$. when the reverse voltage change from $2V$ to $4V$. The reverse ac resistance of the diode is

• A. $1\times {10}^5\Omega$
• B. $3\times {10}^5\Omega$
• C. $2\times {10}^5\Omega$
• D. $4\times {10}^5\Omega$

Answer 1

The correct option is C $2\times {10}^5\Omega$

change in current $=20\mu A-10\mu A=10\mu A$

change in voltage $=hv-2v=2v$

reverse ac resistance $R=\frac{V}{2}$

$=\frac{2}{10\mu A}=2\times {10}^5\Omega$