Question

The reverse bias in a junction diode is changed from $5V$ to $15V$ then the value of current changes from $38$$\mu A$ to $88$$\mu A$. The resistance of junction diode will be

• A. $4\times {10}^5\Omega$
• B. $3\times {10}^5\Omega$
• C. $2\times {10}^5\Omega$
• D. ${10}^6\Omega$

Answer 1

Answer: (C)

$2\times {10}^5\Omega$

Given that:
Change in voltage, $V=15-5=10V$
Change in current, $I=88-38=50$$\mu A$
Hence, resistance of the diode is
$R=\frac{V}{I}=\frac{10}{50\times {10}^{-6}}$

$R=0.2\times {10}^6=2\times {10}^5$