Question

In a simultaneous throw of two dice, what is the probability of getting a doublet?

• A. $\frac{1}{6}$
• B. $\frac{1}{4}$
• C. $\frac{2}{3}$
• D. $\frac{3}{7}$

Answer 1

The correct option is A $\frac{1}{6}$

In a simultaneous throw of two dice
n(S)=(6$\times$6)=36
Let E = event of getting a doublet = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}
$\therefore P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}\frac{6}{36}=\frac{1}{6}$