Question

In a single throw of two dice, what is the probability of getting a total of 11.

• A. $\frac{1}{9}$
• B. $\frac{1}{18}$
• C. $\frac{1}{12}$
• D. $\frac{35}{36}$

Answer 1

The correct option is B $\frac{1}{18}$

Total number of exhautive cases=$6\times 6$

A total of $11$ may be obtained in two ways as $(5,6),(6,5)$.
$\therefore$ P(total of 11)=$\frac{2}{36}$=$\frac{1}{18}$.