In a solid 'AB' having the NaCI structure, 'A' atoms occupy the corners of the cubic unit cell. If all the face centred atoms along one of the axis are removed, then the resultant stoichiometry of the solid is:

A B_{2}

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A_{2} B

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A_{4} B_{3}

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A_{3} B_{4}

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Solution

The correct option is D $A_{3} B_{4}$
1 (d)Na in NaCI has eight corner and six face atoms and thus,A in AB also has them. If we remove face centered atom of one axis, then two face atoms are removed. Thus, effective no. of A atoms becomes 3 and B occupies octahedral holes, the effective no. B is 4. Thus, A₃A₄ is stoichiometry.

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