Question

In a standing wave pattern in a vibrating air column, nodes are formed at a distance of 4.0 cm. If the speed of sound in air is 328 m s⁻¹, what is the frequency of the source?

Answer 1

Given:
Distance between two nodes = 4 cm
Speed of sound in air v = 328 ms⁻¹
Frequency of source f = ?
Wavelength λ = 2 × 4.0 = 8 cm
v = fλ
$\therefore f=\frac{v}{\lambda }=\frac{328}{8\times {10}^{-2}}=4.1\mathrm{KHz}$.

Hence, the required frequency of the source is 4.1 KHz.