In a thermocouple the cold junction is at 300C. The temperature of inversion is found to be 5400C. Then the neutral temperature is
A
270C
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B
510C
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C
285C
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D
240C
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Solution
The correct option is C 285C Tn−Tc=Ti−Tn Tn=temperature at neutral junction Tc=temperature at cold junction Ti=temperature at inversion junction Tn=5702=285C