In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas releases 20J of heat and 8J of work is done on the gas. If initial internal energy of the gas was 30J, what will be the final internal energy?
A
42J
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B
12J
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C
10J
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D
18J
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Solution
The correct option is D18J Heat energy added=change in internal energy+work done 20=(30−U)+8 30−U=12 U=18J