In a thermodynamic process with 2 moles of gas, 30 J of heat is released and 22 J of work is done on the gas. Given that the initial internal energy of the sample was 20 J, the final internal energy is :

72 J

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32 J

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28 J

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12 J

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Solution

The correct option is D 12 J
The change in the internal energy is given by,

$Δ U = U_{f} - U_{i} = q + W$
$U_{f} - U_{i} = - 30 + 22 = - 8$
Now, if initial internal energy is 20, the final internal energy $= 20 - 8 = 12$ .

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In a thermodynamic process with 2 moles of gas, 30 J of heat is released and 22 J of work is done on the gas. Given that the initial internal energy of the sample was 20 J, the final internal energy is :

The correct option is D 12 JThe change in the internal energy is given by,ΔU=Uf−Ui=q+WUf−Ui=−30+22=−8Now, if initial internal energy is 20, the final internal energy =20−8=12.

The correct option is D 12 J
The change in the internal energy is given by,

$Δ U = U_{f} - U_{i} = q + W$
$U_{f} - U_{i} = - 30 + 22 = - 8$
Now, if initial internal energy is 20, the final internal energy $= 20 - 8 = 12$ .