In a thermodynamical process, pressure of a fixed mass of gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas. If internal energy of the gas was 30 J, then the final internal energy will be

42 J

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18 J

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12 J

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60 J

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Solution

The correct option is B 18 J
As $△ U = △ Q - △ W$
therefore $△ U = (- 20) - (- 8) = - 12 J$
$△ U = U_{f} - U_{i} = - 12$
Therefore $U_{f} = - 12 + U_{i} = - 12 + 30 = 18 J$

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In a thermodynamics process, pressure of a fixed mass of gas is changed in such a manner that the gas releases 30 joule of heat and 18 joule of work was done on the gas. If the initial internal energy of the gas was 60 joule, then the final internal energy will be

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In a thermodynamical process, pressure of a fixed mass of gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas. If internal energy of the gas was 30 J, then the final internal energy will be

The correct option is B 18 JAs △U=△Q−△W therefore △U= (−20)−(−8)=−12J △U=Uf−Ui=−12 Therefore Uf=−12+Ui=−12+30=18J

The correct option is B 18 J
As $△ U = △ Q - △ W$
therefore $△ U = (- 20) - (- 8) = - 12 J$
$△ U = U_{f} - U_{i} = - 12$
Therefore $U_{f} = - 12 + U_{i} = - 12 + 30 = 18 J$