Question

In a transformer, number of turns in primary coil are 140 and that in the secondary are 280. If current in primary is 4A then that in the secondary is

• A. 4 A
• B. 2 A
• C. 6 A
• D. 10 A

Answer 1

The correct option is B 2 A

$\frac{V_p}{V_s}=\frac{i_s}{i_p}\Rightarrow i_s=4\times \frac{140}{280}=2A$