Question

In a transistor circuit, when the base current is increased by $50$$\mu A$, keeping collector voltage fixed at $2V$, the collector current increases by $1.0mA$. The current amplification factor of the transistor will be

• A. $10$
• B. $20$
• C. $30$
• D. $40$

Answer 1

The correct option is B $20$

Given that:
$\Delta I_b=50muA=0.05A$
$\Delta I_c=1mA$
The current amplification factor of the transistor is the ratio of change in output current to change in input current at $V_C=2V$ constant is
$\frac{\Delta Ic}{\Delta Ib}=\frac{1}{50}=20$