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B
Right angled and isosceles
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C
Right angled
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D
None of these
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Solution
The correct option is CRight angled Given, a2+b2+c2=ca+ab√3a2+b2+c2−ca−ab√3=0⇒(a√32−b)2+(a2−c)2=0⇒a=2b√3anda=c2Wecansee,a2+b2=c2sinB=ba=√32≠1⇒Notisosceles∴GiventriangleisaRightangledtrianglewhichisnotisosceles. Option C is correct.