In a triangle ABC, ∠A = 110° and AB = AC. Find ∠B and ∠C.
AB = AC (Given)
∠B = ∠C (Angles opposite to equal sides are equal)
In ΔABC, ∠A + ∠B + ∠C = 180° (Sum of the angles of a triangle)
110° + ∠B + ∠C = 180° (Given ∠B = 70°)
2∠C = 180° − 110°
2∠C = 70°
∠C = 35°
∴∠B = ∠C = 35°