Question

In a triangle $ABC,AB=8cm,AC=10cm$ and $\angle B={90}^{\circ }$, then the area of $△ABC$ is

• A. $49c{m}^2$
• B. $36c{m}^2$
• C. $25c{m}^2$
• D. $24c{m}^2$

Answer 1

Answer: (D)

$24c{m}^2$

$A{C}^2=A{B}^2+BC$
$100=64+B{C}^2$
$BC=6$
Area of $△ABC=\frac{1}{2}\times AB\times BC$
$=\frac{1}{2}\times 8\times 6=24c{m}^2$.