In a triangle ABC and DEF, AB=FD and ∠A=∠D. The two triangles will be congruent by SAS axiom if:
A
BC=EF
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B
AC=DE
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C
AC=EF
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D
BC=DE
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Solution
The correct option is DAC=DE In △ABC and △DEF, ∠A=∠D ....(Given) AB=FD ....(Given) and △ABC≅△DFE ....(SAS rule) It is possible, if corresponding sides are equal, AC=ED