Question

In a triangle ABC, $\angle B={28}^o$ and $\angle C={56}^o$. Find the largest and the smallest sides.

Answer 1

In $△ABC$, $\angle A+\angle B+\angle C$ = ${180}^{\circ }$(Sum of all the angles of a is 1${80}^{\circ }$)
$\angle A$ =${180}^{\circ }-({28}^{\circ }+{56}^{\circ })$
$\angle A$ = ${96}^{\circ }$
Largest side = BC [As we know that the largest side of a triangle lies opposite to the largest angle $(\angle A={96}^{\circ })$]
Smallest side = AC [As we know that the smallest side of a triangle lies opposite to the smallest angle $(\angle B={28}^{\circ })$]