In a triangle ABC, $∠ B = 70^{o} .$ Find $∠ A + ∠ C (i n d e g r e e)$ .

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Solution

Using theorem, Sum of interior angles of a triangle is $180^{o}$ .
Hence $∠ A + ∠ B + ∠ C = 180^{o}$
$∠ A + 70^{o} + ∠ C = 180^{o}$ [ $∠ B = 70^{o}$ Given]
$∠ A + ∠ C = 180^{o} - 70^{o} = 110^{o}$

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