In a triangle ABC, D and E are the midpoints of AB, and AC respectively. Also, DE is parallel to BC. If BC = 8 units, find the value of DE.

1 unit

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2 units

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3 units

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4 units

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Solution

The correct option is D 4 units
According to mid-point theorem, in a triangle ABC, with D and E as the midpoints of AB, and AC respectively and DE parallel to BC, then DE = $\frac{1}{2}$ BC.
Here, BC = 8 units.
So, DE = $\frac{1}{2} \times 8$ = 4 units

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In a triangle ABC, D and E are the midpoints of AB, and AC respectively. Also, DE is parallel to BC. If BC = 8 units, find the value of DE.

The correct option is D 4 unitsAccording to mid-point theorem, in a triangle ABC, with D and E as the midpoints of AB, and AC respectively and DE parallel to BC, then DE = 12 BC. Here, BC = 8 units. So, DE = 12×8 = 4 units

The correct option is D 4 units
According to mid-point theorem, in a triangle ABC, with D and E as the midpoints of AB, and AC respectively and DE parallel to BC, then DE = $\frac{1}{2}$ BC.
Here, BC = 8 units.
So, DE = $\frac{1}{2} \times 8$ = 4 units