In a ABC - sin 2 A -sin 2 B -sin 2 C is equal toA- 2 sin A sin B cos CB- 2 sin A cos B cos C- 2 sin A cos B sin CD- 2 sin A sin B sin C

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Conditional Identities

In a ABC , si...

Question

In a $△ A B C,$ ${sin}^{2} A - {sin}^{2} B + {sin}^{2} C$ is equal to

2 sin A sin B cos C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 sin A cos B sin C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 sin A cos B cos C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 sin A sin B sin C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

A + B + C = \frac{π}{2},

{sin}^{2} A + {sin}^{2} B + {sin}^{2} C = 1 - 2 sin A sin B sin C

{cos}^{2} A + {cos}^{2} B + {cos}^{2} C = 2 + 2 sin A sin B sin C

In a right angled triangle ABC, write the value of $s i n^{2} A + s i n^{2} B + s i n^{2} C$ .

△ A B C, \frac{sin 2 A + sin 2 B + sin 2 C}{sin A + sin B + sin C}

△ A B C

∣ ∣ ∣ ∣ \begin{matrix} 1 & a & b 1 & c & a 1 & b & c \end{matrix} ∣ ∣ ∣ ∣ = 0

{sin}^{2} A + {sin}^{2} B + {sin}^{2} C

△ A B C

sin 2 A + sin 2 B - sin 2 C = 4. cos A . cos B . cos C

Join BYJU'S Learning Program