In a uniform electric field, a charge of 3 C experiences a force of 3000 N. The potential difference between two points 1 cm apart along the electric lines of force will be:
A
10 V
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B
30 V
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C
100 V
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D
300 V
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Solution
The correct option is A 10 V Given force = 3000 N on 3 C
We know F=qE ⇒E=Fq E=30003=1000volts/m
We know V=E×d
=1000×1×10−2
=10 volts