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Question

In a uranium reactor whose thermal power is P=100 MW. If the average number of neutrons liberated in each nuclear splitting is 2.5 each splitting is assumed to release an energy E=200 MeV. The number of neutrons generated per unit time is

A
4.5×1018
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B
8.9×1023
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C
8.4×1019
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D
7.8×1018
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Solution

The correct option is D 7.8×1018
Given, P=100 MW ; E=200 MeV

No. of nuclear spliting per second is,

N=PowerEnergy of each splitting

=100 MW200 MeV=100200×1.6×1019

Hence, no. of neutrons liberated, is

=100200×11.6×1019×2.5=12516×1018

=7.8×1018

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

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