In a uranium reactor whose thermal power is P=100MW. If the average number of neutrons liberated in each nuclear splitting is 2.5 each splitting is assumed to release an energy E=200MeV. The number of neutrons generated per unit time is
A
4.5×1018
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B
8.9×1023
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C
8.4×1019
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D
7.8×1018
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Solution
The correct option is D7.8×1018 Given, P=100MW;E=200MeV
No. of nuclear spliting per second is,
N=PowerEnergy of each splitting
=100MW200MeV=100200×1.6×10−19
Hence, no. of neutrons liberated, is
=100200×11.6×10−19×2.5=12516×1018
=7.8×1018
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Hence, (D) is the correct answer.