Question

In a water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm.Find the total radiating surface in the system.

Answer 1

Here, r = 5/ 2 cm = 2.5 cm = 0.025 m, h = 28 m.

Total radiating surface in the system = total surface area of the cylinder

= $2\pi r(h+r)$

= 2 x 22/ 7 x 0.025 (28 + 0.025) $m^2$

= 44x 0 025 x 28. 025/ 7 $m^2$ = 4.4 m² (approx) An