Question

In a water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.

Answer 1

Length of the cylindrical pipe, h = 28 m

Radius of the cylindrical pipe, r = $\frac{5}{2}$ = 2.5 cm = 0.025 m (1 m = 100 cm)

∴ Total radiating surface in the system

= Curved surface area of the cylindrical pipe

$$\begin{gathered} =2\mathrm{\pi }rh \\ =2\times \frac{22}{7}\times 0.025\times 28 \\ =4.4{\mathrm{m}}^2 \end{gathered}$$
Thus, the total radiating surface in the system is 4.4 m².