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Question

In a wind tunnel experiment, the pressures on the upper and lower surfaces of the wings are 0.90 x105 Pa and 0.91 x 105 Pa respectively. If the area of the wing is 40 m2 the net lifting force on the wing is

A
2 x 104 N
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B
4 x 104 N
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C
6 x 104 N
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D
8 x 104 N
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Solution

The correct option is B 4 x 104 N
Given data,
Pressure of the upper surface P2=0.91×105Pa
Pressure of the lower surface P1=0.90×105Pa
Area=40m2
Force=?
Pressure difference which provides the lift
= pressure difference xx Area of the wing
F=(P2P1)×A

F=(0.91×1050.90×105)Pa×ms2

F=0.01×105Pa×40m2

F=4×104N.

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