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Question

In a Young's double slit experiment,the fringe width is found to be 0.4 mm. What will be the new fringe width, if the whole apparatus is immersed in a water of refractive index 4/3 without disturbing the geometrical arrangement?

A
0.30 mm
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B
0.40 mm
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C
0.53 mm
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D
450 mm
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Solution

The correct option is A 0.30 mm
β=λDd;βλGives us,β'β=0.44/3β'=0.30 mm

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