In a Young's double slit experiment the intensity of light at each slit is $I_{0}$ . Interference pattern is observed along a direction parallel to the line $S_{1} S_{2}$ on screen $S$ . The minimum, maximum, and the intensity averaged over the entire screen are respectively

0, 4 I_{0}, 2 I_{0}

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I_{0}, 2 I_{0}, 3 I_{0} / 2

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0, 4 I_{0}, I_{0}

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0, 2 I_{0}, I_{0}

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Solution

The correct option is A $0, 4 I_{0}, 2 I_{0}$
$I_{m} a x = (\sqrt{I_{0}} + \sqrt{I_{0}})^{2} = 4 I_{0}$
$I_{m} i n = (\sqrt{I_{0}} - \sqrt{I_{0}})^{2} = 0$
$I_{a} v g = (I_{0} + I_{0}) = 2 I_{0}$

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In a Young's double slit experiment the intensity of light at each slit is I0. Interference pattern is observed along a direction parallel to the line S1S2 on screen S. The minimum, maximum, and the intensity averaged over the entire screen are respectively

The correct option is A 0,4I0,2I0Imax=(√I0+√I0)2=4I0Imin=(√I0−√I0)2=0Iavg=(I0+I0)=2I0

In a Young's double slit experiment the intensity of light at each slit is $I_{0}$ . Interference pattern is observed along a direction parallel to the line $S_{1} S_{2}$ on screen $S$ . The minimum, maximum, and the intensity averaged over the entire screen are respectively

The correct option is A $0, 4 I_{0}, 2 I_{0}$
$I_{m} a x = (\sqrt{I_{0}} + \sqrt{I_{0}})^{2} = 4 I_{0}$
$I_{m} i n = (\sqrt{I_{0}} - \sqrt{I_{0}})^{2} = 0$
$I_{a} v g = (I_{0} + I_{0}) = 2 I_{0}$