wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be:

A
0.75 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.50 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1 mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.25 mm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.25 mm
Fringe width (β)=λDd
d = 2×103 m

λ=500×109 m

D = 1 m

Now,

β=500×109×12×103

β=52×104

β=2.5×104

β = 0.25 mm

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Diffraction II
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon