In a Young's double slit experiment two slits are separated by 2mm and the screen is placed one meter away. When a light of wavelength 500nm is used, the fringe separation will be:
A
0.75mm
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B
0.50mm
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C
1mm
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D
0.25mm
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Solution
The correct option is D0.25mm Fringe width (β)=λDd d=2×10−3m