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Question

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be:

A
0.75 mm
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B
0.50 mm
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C
1 mm
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D
0.25 mm
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Solution

The correct option is D 0.25 mm
Fringe width (β)=λDd
d = 2×103 m

λ=500×109 m

D = 1 m

Now,

β=500×109×12×103

β=52×104

β=2.5×104

β = 0.25 mm

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