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Zener Diode

In a zener-re...

Question

In a zener-regulated power supply a zener diode with $V_{z} = 6$ volt is used for regulation. The load current is to be $4 m A$ and the unregulated input is $10$ volt. What should be the value of series resistor $R_{s}$ if the current through diode is five times the load current?

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Solution

Appyling $K C L$ at Node -A
$I = (20 + 4) m A = 24 m A$
Applying $K V L$ in the loop
$- 10 V + V_{R} + V_{z} = 0$
As $V_{z} = 6 V$
$\Rightarrow$ $V_{R} = 10 V - 6 V = 4 V$
Also,
By ohm's law
$V_{R} = R_{s} I$
$4 V = R_{s} (24 m A)$
$\frac{4}{24 \times 10^{- 3}} = R_{s}$
$\Rightarrow$ $R_{s} = \frac{10^{3}}{6} = 166.67 Ω$
The value of series resistor is $166.67 Ω$

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