In acidic medium dichromate ion oxidises stannous ion as-xSn 2- yCr 2 O 72- zH - aSn 4- bCr 3- cH 2 OA- The value of x- y is 1- 3B- a - b is 3- 2C- The value of x-y-z is 18D- The value of z - c is 7

The correct options are B a : b is 3 : 2 C The value of x + y + z is 18xSn^2++yCr_2O^2 _7 + zH^+⟶ aSn^4++bCr^3+ + cH_2O Upon Balancing the redox reaction 3Sn^ ...

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Byju's Answer

Standard XII

Chemistry

Ion Electron Method

In acidic med...

Question

In acidic medium dichromate ion oxidises stannous ion as:

$x S n^{2 +} + y C r_{2} O_{7}^{2 -} + z H^{+} ⟶ a S n^{4 +} + b C r^{3 +} + c H_{2} O$

The value of x : y is 1 : 3

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a : b is 3 : 2

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The value of x + y + z is 18

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The value of z - c is 7

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Solution

The correct options are
B a : b is 3 : 2
C The value of x + y + z is 18
$x S n^{2 +} + y C r_{2} O_{7}^{2 -} + z H^{+} ⟶ a S n^{4 +} + b C r^{3 +} + c H_{2} O$

Upon Balancing the redox-reaction

$3 S n^{2 +} + C r_{2} O_{7}^{2 -} + 14 H^{+} ⟶ 3 S n^{4 +} + 2 C r^{3 +} + 2 C r^{3 +} + 7 H_{2} O$

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In acidic medium dichromate ion oxidises stannous ion as: xSn2++yCr2O2−7+zH+⟶aSn4++bCr3++cH2O

The correct options are B a : b is 3 : 2 C The value of x + y + z is 18xSn2++yCr2O2−7+zH+⟶aSn4++bCr3++cH2O Upon Balancing the redox-reaction 3Sn2++Cr2O2−7+14H+⟶3Sn4++2Cr3++2Cr3++7H2O

In acidic medium dichromate ion oxidises stannous ion as:

$x S n^{2 +} + y C r_{2} O_{7}^{2 -} + z H^{+} ⟶ a S n^{4 +} + b C r^{3 +} + c H_{2} O$