In ammonia, $H - N - H$ bond angle is_______.

{106.7}^{0}

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{104.5}^{0}

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{109.5}^{0}

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120^{0}

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Solution

The correct option is A ${106.7}^{0}$
$N H_{3}$ has a trigonal geometry.It should have an angle of $109.5$ , but the actual angle is $106.7$ .The angle is decreased because of electron pair repulsion

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