Question

In an $A.P$ ${17}^{th}$ term is $7$ more then is ${10}^{th}$ term. Find the common difference ?

Answer 1

Given,

$T_{17}=7+T_{10}$

$T_n=a+(n-1)d$

$a+16d=7+a+9d$

$16d-9d=7$

$7d=7$

$\therefore d=1$

common difference is equal to 1