Question

In an A.P. the sum of $3$ consecutive term is $27$ and their product is $504$. Find the terms.

Answer 1

According to the problem,

Assume the term

$a-d,a,a+d$

As Given,

$a-d+a+a+d=27$

$3a=27$

$a=9$

And,

$\left(a-d\right)\left(a\right)\left(a+d\right)=504$

$\left(a\times a-d\times d\right)=56$

$81-d\times d=56$

$d\times d=81-56$

$d\times d=25$

$d=5$

Therefore the 3 consecutive terms are

$\left(9-5\right),\left(9\right),\left(9+5\right)$

i.e $4,9,13$