In an AC circuit, the potential across an inductance and resistance joined in series are respectively $16 V$ and $20 V$ . The total potential difference across the circuit is

20.0 V

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25.6 V

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31.9 V

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33.6 V

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Solution

The correct option is B $25.6 V$
Voltage
$V = \sqrt{V_{R}^{2} + V_{C}^{2}} = \sqrt{{(20)}^{2} + {(16)}^{2}} = 25.6 V$

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In an AC circuit, the potential across an inductance and resistance joined in series are respectively 16V and 20V. The total potential difference across the circuit is

The correct option is B 25.6VVoltageV=√V2R+V2C=√(20)2+(16)2=25.6V

In an AC circuit, the potential across an inductance and resistance joined in series are respectively $16 V$ and $20 V$ . The total potential difference across the circuit is

The correct option is B $25.6 V$
Voltage
$V = \sqrt{V_{R}^{2} + V_{C}^{2}} = \sqrt{{(20)}^{2} + {(16)}^{2}} = 25.6 V$