In an ac circuit, the potential differences across an inductance and resistance joined in series are, respectively, $16 V$ and $20 V$ . The total potential difference across the circuit is

20 V

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25.6 V

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31.9 V

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53.5 V

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Solution

The correct option is B $25.6 V$
In phasor, $V_{R} = 20 ∠ 0$ ; $V_{L} = 16 ∠ (- 90)$
Total potential difference is = $V_{R} + V_{L} = 25.6 ∠ (- 38.66)$
Magnitude of total potential difference = $25.6 V$

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In an ac circuit, the potential differences across an inductance and resistance joined in series are, respectively, 16 V and 20 V. The total potential difference across the circuit is

The correct option is B 25.6 VIn phasor, VR=20∠0; VL=16∠(−90)Total potential difference is = VR+VL=25.6∠(−38.66)Magnitude of total potential difference =25.6V

In an ac circuit, the potential differences across an inductance and resistance joined in series are, respectively, $16 V$ and $20 V$ . The total potential difference across the circuit is

The correct option is B $25.6 V$
In phasor, $V_{R} = 20 ∠ 0$ ; $V_{L} = 16 ∠ (- 90)$
Total potential difference is = $V_{R} + V_{L} = 25.6 ∠ (- 38.66)$
Magnitude of total potential difference = $25.6 V$