Question

In an adsorption experiment, a graph between log$\frac{x}{m}$ versus logP was found to be linear with a slope of ${45}^o$. The intercept of the log(x/m) axis was found to be 0.3010. Calculate the amount of gas adsorbed per gram of charcoal under a pressure of 0.5 atm

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is A 1

from $\frac{x}{m}=k{P}^{1/n}\left(i\right)$
$log\frac{x}{m}=logk+\frac{1}{n}logP$
Now $\frac{1}{n}=tan{45}^0=1,logk=0.3010\text{so}k=2$
and $P=0.5atm$
Putting all the values in first equation we get
$\frac{x}{m}=1$