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Standard XII

Chemistry

Derivation of Kp and Kc

In an alkalin...

Question

In an alkaline solution, the following equilibrium exists.

$S^{2 -} + S ⇋ S_{2}^{2 -}, K_{1} = 12$
$S_{2}^{2 -} + S ⇋ S_{3}^{2 -}, K_{2} = 11$

What is the equilibrium constant for the given equilibrium?

$S_{3}^{2 -} ⇋ S^{2 -} + 2 S$

23

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132

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1 / 132

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1 / 32

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Solution

The correct option is B $1 / 132$
$K_{1} = \frac{[S_{2}]^{2 -}}{[S] [S^{2 -}]} = 12$

$K_{2} = \frac{[S_{3}]^{2 -}}{[S] [S_{2}]^{2 -}} = 11$

For the required equation, we have to add equation number $1$ and $2$ and reverse it.

Now, adding equation means to multiply equilibrium constant.

But after adding equation we get the reverse reaction of the required one. Hence we have to reverse the reaction. Now, reversing the reaction means to find the reciprocal of the equilibrium constant.

Hence, take the reciprocal to get the required $K$ .

$K = \frac{1}{K_{1} \times K_{2}} = \frac{1}{132}$

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Similar questions

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Sulphide ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equilibrium constant for the formation of $S_{2}^{2 -}$ and $S_{3}^{2 -}$ from S and $S^{2 -}$ ions are 1.7 and 5.3 respectively. Equilibrium constant for the formation of $S_{3}^{- 2}$ from S is:

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In an alkaline solution, the following equilibrium exists.S2−+S⇋S2−2,K1=12S2−2+S⇋S2−3,K2=11What is the equilibrium constant for the given equilibrium?S2−3⇋S2−+2S

In an alkaline solution, the following equilibrium exists.

$S^{2 -} + S ⇋ S_{2}^{2 -}, K_{1} = 12$
$S_{2}^{2 -} + S ⇋ S_{3}^{2 -}, K_{2} = 11$

What is the equilibrium constant for the given equilibrium?

$S_{3}^{2 -} ⇋ S^{2 -} + 2 S$