In an AM receiver, the local oscillator frequency of the mixer is set at the higher of the two possibilities. Due to improper filtering by the RF stage, both 600 kHz and 1000 kHz carrier frequencies are crossing IF stage simultaneously, when the receiver is tuned to a station. The intermediate frequency $(f_{I F})$ of the receiver is _____ kHz
200

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Solution

The correct option is A 200
$f_{i} = f_{c} + 2 f_{I F}$

$f_{c} = 600 k H z$

$f_{i} = 1000 k H z$

So, $2 f_{I F} = f_{i} - f_{c} = 1000 - 600 = 400 k H z$

$f_{I F} = 200 k H z$

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