In an AP, if $d = - 2, n = 5$ and $a_{n} = 0$ , then the value of $a$ is

10

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5

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- 8

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8

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Solution

The correct option is D $8$
Given:
$d = - 2$
$n = 5$
$a_{n} = 0$
We know:
$a_{n} = a + (n - 1) d$
$∴ 0 = a + (5 - 1) (- 2)$
$∴ a = 8$
Hence, the value of $a$ is $8$ .

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