In an apparatus, the electric field was found to oscillate, with an amplitude of 18 ${V m}^{- 1}$ . The rms of the oscillating magnetic field is

6 \times 10^{- 8} T

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4.23 \times 10^{- 8} T

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9 \times 10^{- 8} T

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7 \times 10^{- 8} T

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Solution

The correct option is A $6 \times 10^{- 8} T$
$\begin{matrix} G i v e n E_{0} = 18 v / m W e k n o w t h a t, B_{0} = \frac{E_{0}}{c} = \frac{18}{\begin{matrix} 3 \times 10^{8} \end{matrix}} = 6 \times 10^{- 8} T H e n c e, t h e o p t i o n A i s t h e c o r r e c t a n s w e r . \end{matrix}$

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In an apparatus, the electric field was found to oscillate, with an amplitude of 18Vm−1. The rms of the oscillating magnetic field is

The correct option is A 6×10−8TGivenE0=18v/mWeknowthat,B0=E0c=183×108=6×10−8THence,theoptionAisthecorrectanswer.

In an apparatus, the electric field was found to oscillate, with an amplitude of 18 ${V m}^{- 1}$ . The rms of the oscillating magnetic field is

The correct option is A $6 \times 10^{- 8} T$
$\begin{matrix} G i v e n E_{0} = 18 v / m W e k n o w t h a t, B_{0} = \frac{E_{0}}{c} = \frac{18}{\begin{matrix} 3 \times 10^{8} \end{matrix}} = 6 \times 10^{- 8} T H e n c e, t h e o p t i o n A i s t h e c o r r e c t a n s w e r . \end{matrix}$