Question

In an apparatus, the electric field was found to oscillate with an amplitude of 18 V/m. The magnitude of the oscillating magnetic field will be

• A. $4\times {10}^{-6}$ T
• B. $6\times {10}^{-8}$ T
• C. $9\times {10}^{-9}$ T
• D. $11\times {10}^{-11}$ T

Answer 1

The correct option is B $6\times {10}^{-8}$ T

$c=\frac{E}{B}\Rightarrow B=\frac{E}{c}=\frac{18}{3\times {10}^8}=6\times {10}^{-8}T.$