In an electric circuit the applied alternating emf is given by $E = 100 sin (314 t)$ volts and current flowing $I = sin (314 t + \frac{π}{3})$ , Then, the impedance of the circuit is $(i n Ω)$

\frac{100}{\sqrt{2}}

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100

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100 \sqrt{2}

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Solution

The correct option is B $100$
Phasor of $E = 100 ∠ (π / 2)$
phasor of $I = 1 ∠ (π / 2 + π / 3)$
phasor of impedance $= \frac{E}{I} = 100 ∠ (- π / 3)$
impedance magnitude $= 100 Ω$

Suggest Corrections

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E = 300 s i n [(100 π) t]

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A C

E = E_{0} sin ω t

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