In an electrical circuit two resistors of 2 Ω and 4 Ω respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be:
A
5J
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B
10J
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C
20J
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D
30J
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Solution
The correct option is C20J Equivalent resistance for resistors connected in series, R=R1+R2=2+4=6Ω Voltage, V=6V Current, I=VR=66=1A Current flowing through the resistors are same. Heat dissipated by the 4 Ω resistor in 5 s is given by, Heat=I2Rt=(1)2×4×5=20J