Question

In an estimation of S by Carius method 0.2175g of the compound gave 0.5825g of $BaS{O}_4$. Percentage of S is :

• A. $36.78$ %
• B. $35.50$ %
• C. $36.98$ %
• D. $35.69$ %

Answer 1

The correct option is A $36.78$ %

% S = $\frac{Atomicmassofs}{malmassofBas{o}_4}\times \frac{massofBas{o}_4\times con}{massofcomped}$
= $\frac{32}{233}\times \frac{0.5825\times 100}{0.2175}$
$\therefore s=36.78\%$